find the 10th and 15th term of series 7, 14, 28,.....
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Answered by
1
GIVEN :
a = 7
d = 3 (a2 - a1)
Now, a10 = a + 9 d = 7 + 63 = 70
and. a15 = a + 14d = 7 + 98 = 105
I HOPE THIS HELPS YOU!
a = 7
d = 3 (a2 - a1)
Now, a10 = a + 9 d = 7 + 63 = 70
and. a15 = a + 14d = 7 + 98 = 105
I HOPE THIS HELPS YOU!
Answered by
0
First term, a₁ = 7 ,
Second term. a₂ = 14
Third term,a₃ = 28
a₂/a₁ = 14/7 = 2
a₃/a₂ = 28/14 = 2
a₂/a₁ = a₃/a₂ = 2
Therefore,the given series are in GP.
common ratio,r = 2 ; a = 7
nth term of GP : an = ar^(n-1)
10th term, a₁₀ = ar⁹ = 7(2)⁹
= 7(512)
= 3584
15th term,a₁₅ = ar¹⁴ = 7(2)¹⁴
= 7(16384)
= 114688
Hope it helps
Second term. a₂ = 14
Third term,a₃ = 28
a₂/a₁ = 14/7 = 2
a₃/a₂ = 28/14 = 2
a₂/a₁ = a₃/a₂ = 2
Therefore,the given series are in GP.
common ratio,r = 2 ; a = 7
nth term of GP : an = ar^(n-1)
10th term, a₁₀ = ar⁹ = 7(2)⁹
= 7(512)
= 3584
15th term,a₁₅ = ar¹⁴ = 7(2)¹⁴
= 7(16384)
= 114688
Hope it helps
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