Find the 10th and 20th terms of the Gp
With first term 3 and common ratio 2.
Answers
Answered by
1
Answer:
t₁₀ = 1536
t₂₀ = 15,72,864
Step-by-step explanation:
given, the first term of the G.P , a = 3
and the common ratio, of G.P, r = 2
=> we know in a G.P, the nth term, tₙ = arⁿ⁻¹
=> t₁₀ = 3 * 2⁹ = 3*512 = 1536
and t₂₀ = 3*2¹⁹ = 3 * 2⁹*2¹⁰ = 3*512*1024 = 1536*1024 = 15,72,864
Answered by
0
Answer:
Tn=ar^(n-1)
Step-by-step explanation:
T10=3*2^(10-1)
=3*2^9
=3*512
=1536
similarly,
T20=3*2^19
=1,572,864
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