Math, asked by praveenmalaviya11, 2 months ago

Find the 10th and 20th terms of the Gp
With first term 3 and common ratio 2.​

Answers

Answered by ravi2303kumar
1

Answer:

t₁₀ = 1536

t₂₀ = 15,72,864

Step-by-step explanation:

given, the first term of the G.P , a = 3

and the common ratio, of G.P,  r = 2

=> we know in a G.P, the nth term, tₙ = arⁿ⁻¹

=> t₁₀ = 3 * 2⁹ = 3*512 = 1536

and t₂₀ = 3*2¹⁹ = 3 * 2⁹*2¹⁰ = 3*512*1024 = 1536*1024 = 15,72,864

Answered by k99hitesh
0

Answer:

Tn=ar^(n-1)

Step-by-step explanation:

T10=3*2^(10-1)

=3*2^9

=3*512

=1536

similarly,

T20=3*2^19

=1,572,864

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