Question

Find the 10th and nth term of the series 3,7, 11, 15,....​

Answer 1

Answer:

a= 3

d= 7-3

d=4

a10= a+(n-1)d

a10=3+(10-1)4

a10=3+(9×4)

a10=3+36

a10=39

Answer 2

Step-by-step explanation:

3,7,11,15,.... are in a.p with common difference '4'

an = a + (n-1)d

now,

a10 = 3 + (10 - 1) 4

= 3 +36 = 39

an = 3 + (n-1)4

= 3 +4n -4

= 4n -1

hope it helps you ☺️

please mark me as brainliest