Question

find the 10th and P terms of the GP (2,6,18,54,.....)​

Answer 1

Step-by-step explanation:

a = 2 , r = 6/2 = 3

So, 10-th term of this GP is,

$t10 = a {r}^{(n - 1)} = 2 \times {3}^{9}$

and p-th term is,

$tp = a {r}^{(p - 1)} = 2 \times {3}^{(p - 1)}$