Question

Find the 10th term 0f an AP 13, 8, 3, .…..​

Answer 1

Step-by-step explanation:

Series is AP, a = 13, d = -5

a10 = a + 9d

= 13 + 9(-5)

= 13 - 45

= -32

Answer 2

Answer:

The 10th term of the arithmetic progression is $-32$.

Step-by-step explanation:

The $n^{th}$ term of an arithmetic progression is,

$A_n=a+(n-1)d$

where $a$ is the first term and $d$ is the common difference.

The given arithmetic progression is 13,8,3,...

The first term,

$a=13$

The common difference,

$d= 8-13=3-8=-5$

So $10^{th}$ term of the AP is

$A_{10}=13+(10-1)\times(-5)=13+9\times (-5)=13-45=-32$

Hence the 10th term of the arithmetic progression is $-32$.