find the 10th term from end of the ap 8,10,12...126
Answers
Answered by
308
Hi ,
8 , 10 ,12 , ..., 124 , 126 is an A.P
Rearranging the given A.P in
reverse order we get,
126 , 124 , ....., 12 , 10 , 8
First term = a = 126
Common difference = a2 - a1
d = 124 - 126
d = -2
n = 10
____________________________
We know that ,
n th term = an = a + ( n - 1 ) d
____________________________
10th term = a10
a10 = a + 9d
= 126 + 9 ( - 2 )
= 126 - 18
a10 = 108
Therefore ,
10th term from the end of the A.P
= 108
I hope this helps you.
***
8 , 10 ,12 , ..., 124 , 126 is an A.P
Rearranging the given A.P in
reverse order we get,
126 , 124 , ....., 12 , 10 , 8
First term = a = 126
Common difference = a2 - a1
d = 124 - 126
d = -2
n = 10
____________________________
We know that ,
n th term = an = a + ( n - 1 ) d
____________________________
10th term = a10
a10 = a + 9d
= 126 + 9 ( - 2 )
= 126 - 18
a10 = 108
Therefore ,
10th term from the end of the A.P
= 108
I hope this helps you.
***
Answered by
148
all the best for your board exams......
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Similar questions
118 = (n-1)2
59 = n-1
n = 60
the pth term from the last
t(n-p+1) = a+(n-p)d
t(60-10+1) = 8 +(60-10)2
t51 = 108