Find the 10th term from the end of the A.P., 17, 14, 11,....-40
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Answered by
2
a= 17
d= -3
l= -40
n= 10
Formula= [ l- (n-1) d ]
= [-40- (10-1) -3 ]
= [ -40+ (9×3) ]
= -40 + 27
= -13
Answered by
0
a= 17
d= -3
l= -40
n= 10
Formula= [ l- (n-1) d ]
= [-40- (10-1) -3 ]
= [ -40+ (9×3) ]
= -40 + 27
= -13
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