Question

Find the 10th term from the end of the A.P. 5,7,9,......,159



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Answer 1

$\underline{\textsf{Given:}}$

$\textsf{A.P is 5,7,9.........159}$

$\underline{\textsf{To find:}}$

$\textsf{10 th term from the end of the A.P}$

$\underline{\textsf{Solution:}}$

$\textsf{when the given A.P is reversed, we get}$

$\mathsf{159,157,...............7,5}$

$\textsf{Here, a=159, d=-2}$

$\boxed{\begin{minipage}{6cm} \\\textsf{The n th term of A.P a, a+d, a+2d.......}\\\\\textsf{is}\;\mathsf{t_n=a+(n-1)d}\\ \end{minipage}}$

$\textsf{10 th term from the end of the A.P}$

$\mathsf{=t_{10}}$

$\mathsf{=a+9d}$

$\mathsf{=159+9(-2)}$

$\mathsf{=159-18}$

$\mathsf{=141}$

$\underline{\textsf{Answer:}}$

$\textsf{10 th term from the end of the given A.P is 141}$

Find more:

If pth term of an ap is q and qth term is p then show that its nth term is (p+q-n)

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