Question

Find the 10th term from the end of the A.P.8,10,123,......126​

Answer 1

Given:-AP=8,10,12......126

Reverse of the AP 126,124,122 ......10,8

Here a=126,d=a2-a1=124-126=-2,an=8

an=a+(n-1)d

a10=126+(10-1)*(-2)

a10=126+9*(-2)

a10=126-18

a10=108

Answer 2

Answer:

670

Step-by-step explanation:

Given AP: 8,10,123,....126

Reverse the order as we need the 10th term from last. => AP: 126,....123,10,8

a = 126; l = 8; n= 10;

an= n/2 [a+l]

an = 10/2 [126+8]

an= 5× 134

an = 670