Question

find the 10th term from the end of the ap 8 , 10, 12...126

Answer 1

A.P:8,10,12......126.

From last 126.......12,10,8

a=126

d=10-12 = -2

An = a+(n-1)d
A10 = 126+(10-1)-2
= 126-18
A10 = 108

Hope it helps.

Answer 2

Given AP is 8,10,12,....126.

The last term of AP is 126.

Given Question is to find the 10th term from the end.

First-term a = 126.

common difference d = 8 - 10

                                     = -2.

We know that sum of n terms of an AP an = a + (n - 1) * d

10th term from the end a10 = 126 + (10 - 1) * (-2)

                                              = 126 - 18

                                              = 108.


Hope this helps!