Find the 10th term from the end to beginning of the ap 4,9,14,....,254
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4,9,14,....,254 in AP
1st term a1 = 4
Common difference d = 5
Last term an = 254
an = a + (n-1) d
254 = 4 + (n-1) 5
250 = (n-1) 5
50 = n-1
50 + 1 = n
n = 51
254 is 51 term in AP series
last to 10th term in AP series is 42 term
an = a + (n-1) d
a42 = 4 + (42-1) 5
a42 = 4 + 41 × 5
a42 = 4 + 205
a42 = 209
The 10th term from the end to beginning of the AP series 4,9,14,....,254 is 209
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