find the 10th term from the last of the AP 8,10,12,....,126.
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a = 8
d = 2
an = 126
a + (n - 1)d = 126
8 + (n - 1)2 = 126
8 + 2n - 2 = 126
2n = 120
n = 60
10th term from the last = a50
a50 = a + 49d
= 8 + 98
= 106
10th term from the last = 106
d = 2
an = 126
a + (n - 1)d = 126
8 + (n - 1)2 = 126
8 + 2n - 2 = 126
2n = 120
n = 60
10th term from the last = a50
a50 = a + 49d
= 8 + 98
= 106
10th term from the last = 106
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