Find the 10th term of a G.P whose 3rd term is 24 and 6th term is
192.
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Step-by-step explanation:
Let the first term of G.P. be a and the common ratio be r. Given, T3 = 24 ⇒ ar2 = 24 … … … (i) And T6 = 192 ⇒ ar5 = 192 … … … (ii) Dividing eq. (i) by (ii), we get a r 5 a r 2 ar5ar2 = 192 24 19224 ⇒ r3 = 8 or r = 2 Putting the value of r in eq. (i), we get a(2)2 = 24 ⇒ a = 6 ∴ T10 = ar9 = 6(2)9 = 3072/in-a-g-p-the-3rd-term-is-24-and-6thterm-is-192-find-the-10th-term
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