Find the 10th term of an AP: √2, 3√2, 5√2, 7√2....
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a=1√2 ,d=3√2-1√2=2
tn=a+(n-1)d
t10=1√2+(10-1)2
t10=1√2+9×2
t10=1√2+18
t10=19√2
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