Question

Find the 10th term of an ap 2,4, 6 , 8, 10, .................28

Answer 1

Here first term is 2 and common difference is 2. Thus 10th term is a+9d=2+2*9=20.

Answer 2

Answer:

Required 10 th term is 20.

Step-by-step explanation:

Given series is 2,4, 6 , 8, 10, .................28.

First term of the series is 2 and common difference is (4-2) = 2

Here we want to find 10 th term of the series.

We know,

$a_n = a + (n - 1)d$

Where $a_n$ is nth term.

n is number of term and a is first term of the series and d is common difference.

Here,

$a = 2 \\ d = 2 \\ n = 10$

So,

$a_{10} = 2 + (10 - 1) \times 2 \\ = 2 + 9 \times 2 \\ = 2 + 18 \\ = 20$

Required 10 th term is 20.

Here applied formula,

$a_n = a + (n - 1)d$

One more important formula of AP series,

Sum of the series,

$s_n = \frac{n}{2} ( first \: term + last \: term)$

Know more about Arithmetic progression:

1) https://brainly.in/question/4219484

2)https://brainly.in/question/2768711

#SPJ2