Find the 10th term of an ap 2 6 10 14
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Answer:
t1= 2, t2= 6, t3= 10, t4= 14
a= 2, d= 6–2 = 4
Step-by-step explanation:
t10 = a+ ( n–1 ) d
= 2 + (10–1) 4
= 2 +(9) 4
= 2+ 36
= 38
Therefore t10 = 38.
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