Question

find the 10th term of an AP 5,7,9...​

Answer 1

Answer:

23

Step-by-step explanation:

Here, first term(a) = 5

Common difference(d) = 7-5 = 2

So, 10th term(a10) = a+(n-1)d

= 5 + 9×2

= 23

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Answer 2

Answer:

$\huge\underbrace{\color{magenta}{Answer}}$

$\huge{\underline{\underline{Given}}}$

AP ↦5,7,9,...

$a1 = 5$

$d = a2 - a1$

$d = 7 - 5$

$d = 2$

$\huge{\underline{\underline{To\: find}}}$

$a10$

$\huge{\underline{\underline{Proof:-}}}$

$a10 = a1 + 9d$

$a10 = 5 + 9 \times 2$

$a10 = 5 + 18$

$a10 = 23$

$\huge\fbox\fcolorbox{pink}{red}{a10\: = \: 23}$