Question

find the 10th term of an ap whose 6th term is 12 and fifth term is 22

Answer 1

a6=12

a5=22                                

a+5d=12

a+4d=22

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d=-10

a+5(-10)=12

a-50=12

a=12+50

a=62

A10=a+9d

      =62+9(-10)

        =62-90

        =-28

Answer 2

6th term = a +5d=12
5th term = a+4d=22
now
a+4d=22
-
a+5d=12
hence
d=-10
put d=-10
hence a +4*-10=22
a-40=22
a=22+40
a=62
now solve
10th term=a+9d by putting the values