Question

Find the 10th term of an AP whose sum is n^2-3n

Answer 1

(100-30)-(81-27)
70-54=16

Answer 2

In an Arithmetic Progression we can find the term value by the formula:-

Tn = Sn - Sn-1
Where n stands for term number.
We know Sum is n^2 - 3n

So,T10 = S10 - S9
= (10^2 - 10×3) - (9^2 - 9×3)
= (100 - 30) - (81 - 27)
= 70 - 54
= 16

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