Question

Find the 10th term of an arithmetic sequence if a1=-13 and d=8.​

Answer 1

Hello,

a = –13

d = 8

a10 = ?

Thus, n=10

An = a + (n–1) × d

a10 = –13 + (10–1) × 8

a10 = –13 + 72

a10 = – 59

Hope You got the answer.

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Answer 2

SOLUTION

TO DETERMINE

The 10th term of an arithmetic sequence if a₁ = - 13 and d = 8.

EVALUATION

Here it is given that for the given arithmetic sequence a₁ = - 13 and d = 8.

First term = a₁ = - 13

Common Difference = d = 8

Hence the required 10th term of the sequence

$\sf{ = a_{10}}$

= a₁ + ( 10 - 1 ) d

= a₁ + 9d

= - 13 + ( 9 × 8 )

= - 13 + 72

= 59

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