Question

Find the 10th term of AP 7,15,23​

Answer 1

Answer:

plz Mark brilliant

Step-by-step explanation:

Method: I

rth term from end is given by

= Tn - (r - 1) d or

- r + 1)th term from beginning where n = (n - r is total no. of terms.

m = 96, n = 26

:: T26 from last = T(96-26+1) from beginning

=T_71 from beginning

= a + 70d

= 7+ 70 (8) = 7+ 560 = 567

Method: II

d=15-7-8

.. from last, a = 767 and d = -8

..T26 = a + 25d = 767 +25(-8)

= 767 - 200

= 567.

Answer 2

Answer:

The $10^{th}$ term of the AP $7,15,23$ is $a_{10} =79$

Step-by-step explanation:

General term of an AP is given by

$a_{n} =a+(n-1)d$, where

$a$ is the first term, $d$ is the common difference, $n$ is the number of term.

Here, $a=7,\ d=15-7=8,\ n=10$

substituting in $a_{n}$

$a_{10} =7+(10-1)8$

     $=7+9(8)\\\\=7+72\\\\=79$

hence the answer

thank you