Find the 10th term of ap sum of the 3rd term and 8th term is 7 and some of the 7th term and 14th term is–3
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Answer:
a10 = -1
Step-by-step explanation:
a3 + a8 = 7
a + 2d + a + 7d = 7
2a + 9d = 7...(1)
and,
a7 + a14 = -3
a + 6d + a + 13d = -3
2a + 19d = -3
using elimination method,
19d - 9d = -3 -7
10d = -10
d = -1
putting d in eq 1
2a = 7 + 9
a = 16/2
a = 8
and now, a10 = a + 9d
a10 = 8 - 9
a10 = -1
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