find the 10th term of AP whose a=1 and d=2
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Answered by
0
Answer:
a10= a+(n-1)d
a10= 1+(10-1)2
a10 = 1+18 = 19
Answered by
0
Answer:
10th term of ap is a+9d
a=1 and d=1
then, 1+9×1
= 10
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