Question

find the 10th term of geometric progression 5, 25, 125​

Answer 1

Step-by-step explanation:

625 it is an easy question

Answer 2

Answer:

$r \: = \frac{25 }{5} \: = 5 \\ a = \: 5 \\ n \: = \: 10\\ t10 \: = a \times {r}^{n - 1} \\ t10 \: = 5 \times {5}^{9} \\ t10 \: = {5}^{10}$

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