find the 10th term of geometric progression if 2nd term is 43 and 4th term is 9
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Answer:
-93
Step-by-step explanation:
a+d = 43
a + 3d=9
43-d+3d=9
2d = -34
d= -17
a10= a+ 9d
= 60 +(-17)*9
= - 93
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