Question

Find the 10th term of given G.P 512, 256, 128

Answer 1

Answer:

hope so helped u.....plzzz follow me

Answer 2

Given:

The geometric progression is 512, 256, 128

To find:

The 10th term

Solution:

The formula to find the nth term of G.P is as follows,

$T_n=a\times r^{(n-1)}$

First term of the series a=512

Common ratio, $r = \frac{256}{512} \text{ or } \frac{128}{256} = \frac{1}{2}$

n is 10

On substituting the known values in the above formula we get,

$\Rightarrow T_n=512\times(\frac{1}{2})^{(10-1)}\rightarrow512\times(\frac{1}{2})^{(9)}\\\\ \Rightarrow T_n=512\times\frac{1^9}{2^9}\rightarrow512\times\frac{1}{512}\\\\ \therefore T_n=\frac{512}{512}\rightarrow1$

Therefore, the 10th term of the given Geometric Progression is 1.

Learn more about Geometric Progression:

For each geometric progression find the common ratio ‘r’, and then find an(i) 3, 3/2, 3/4, 3/8, ......... (ii) 2, −6, 18, −54(iii) −1, −3, −9, −18 .... (iv) 5, 2, 4/5, 8/25, .........

https://brainly.in/question/5483880

In a geometric progression the 4th term is 8 and the 8th is 128/625.Find the Geometric progression. ​

https://brainly.in/question/14415968