Question

find the 10th term of GP3/2,3/4,3/8••••••

Answer 1

a1 = 3/2

a2 = 3/4

a3 = 3/8

The first term a = 3/2

The common ratio (r) = a2/a1

===> 3/4 / 3/8 ==> 0.75 / 0.375 ===> 2

r = 2

nth term of GP :- an = a.r ( n - 1 )

10th term of GP :- a . r ( 10 - 1 )

===> a . r 9

===> ( 3/2) × (2)9

===> ( 1.5 ) × ( 512)

===> 768