Question

find the 10th term of the AP 2,7,12........​

Answer 1

Answer:

47

Step-by-step explanation:

d = 5, a = 2, n = 10

a_n = a + (n - 1)d

a 10 = 2 + (10 - 1) 5

= 2 + 9 X 5

= 2 + 45

= 47

Answer 2

Answer:-

$\small\sf{a=2}$

$\small\sf{d=7-2=5}$

$\small\sf{n=10}$

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$\small\sf{an=a+(n-1)d}$

$\small\sf{a10=2+(10-1)5}$

$\small\sf{2+45}$

$\small\sf{47}$

Therefore, the 10th term of the given AP is 47.