Question

Find the 10th term of the AP.
5.-1.3.7​

Answer 1

Step-by-step explanation:

Let term n= 1/(2n+1)(2n+3) - 1/(2n+1)(2n-1). = -4/(2n+1)(2n-1)(2n+3). Therefore, term n= 1/-4 [ 1/(2n+1)(2n+3) - 1/(2n+1)(2n-1) ]. We find this to be a telescopic sum. Therefore answer is,. n(n+2)/3(2n+1)(2n+3). Thank you