find the 10th term of the AP whose sum of n term is given by 2n^2 + 3
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Step-by-step explanation:
Sn = 2n^2 +3
S1= 2(1)^2 + 3 = 2+3 =5 = a1
S2= 2(2)^2 + 3 = 2×4+3= 8+3 =11
Sn -S1 = a2
4 - 3 = 1
d= 1 - 3
= -3
thus, A.P is 3,1,...
a10 = a + 9d
= 3 + 9×(-3)
= 3 + (-27)
= 3 - 27
= -24
thus, a10 = -24
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