Find the 10th term of the sequence √2,√8,√18
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√2 , √8 ,√18.......
It can be also written as
√2 , 2√2 , 3√2.........
Here a = √2
d = 2√2 - √2 =√2
10th term = a + (n-1)d
n = 10
√2 + (10-1)√2 = √2 + 9√2 = 10√2
Therefore 10th term = 10√2
It can be also written as
√2 , 2√2 , 3√2.........
Here a = √2
d = 2√2 - √2 =√2
10th term = a + (n-1)d
n = 10
√2 + (10-1)√2 = √2 + 9√2 = 10√2
Therefore 10th term = 10√2
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AP : √2, √8, √18
d = √8 - √2 = 2√2 -√2 = √2
a10 = a + (n-1)d
= √2 + (10-1) √2
= √2 + 9 √2
= 10√2
That's why 10th term is 10√2
d = √8 - √2 = 2√2 -√2 = √2
a10 = a + (n-1)d
= √2 + (10-1) √2
= √2 + 9 √2
= 10√2
That's why 10th term is 10√2
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