find the 10th term of the sequence √2,√8,√18......
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a1=√2 a2=2√2. a3=3√2...
d=√2
an = a+(n-1)d
a10=√2+9√2
a10=10√2
so 10th term is 10√2
d=√2
an = a+(n-1)d
a10=√2+9√2
a10=10√2
so 10th term is 10√2
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