Question

Find the 10th term of the sequence √2,√8,√18....... Solve

Answer 1

a=root 2

d=2

an= a+(n-1)d

a10=root2  +18 ans

Answer 2

Make it in the form of√2

√2=√2

√8=2√2

√18=3√2

d= 2√2-√2=√2

10th term =a+9d

=√2+9×√2

=10√2