Question

Find the 10thterm of arithmetic progression 2, 7, 12----using formula.
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Answer 1

Step-by-step explanation:

a=2 d= 7-2=5 , n = 10 ,an =?

aⁿ = a+ ( n - 1) d

aⁿ = 2+(10-1)5

aⁿ = 2+9×5

aⁿ = 2+45

aⁿ = 47. ----------Ans

II pattern

a10 = a+9d

= 2+9×5

= 2+45 =47

Hope its help u

Answer 2

Answer:

47

Step-by-step explanation:

.

Given -

A. P. (Arithmetic Progression) = 2, 7, 12....

.

To find -

10 th term of AP (aⁿ)

.

Solution -

.

Here

$a_{1} = 2 \\ a_{2} = 7$

so common difference (d) =

$d = a_{2} - a_{1} \\ = 7 - 2 \\ = 5$

To find the 10th term (a n)

.

$a_{n} = a_{1} + (n - 1)d \\ \\ (substitute \: the \: values) \\ \\ = > 10th = 2 + (10 - 1)5 \\ \\ = > 10th = 2 + (9 \times 5) \\ \\ = > 10th = 2 + 45 \\ \\ = > 10th = 47$

Hence 10th term of A.P. = 47

hope it helps.