find the 11 term from the the last term of ap. 27,23,19,....,-65
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Answered by
1
In this AP,
a = 27, d= -4, an = -65.
On reversing the order, AP becomes:
-65, -61,..............19,23,27
Here, a= -65, d= 4, an= 27.
Now,
a11= a + (11-1)d
a11 = -65 + 10* 4
= -65 + 40
= -25.
Therefore, the eleventh term from the last is -25.
Hope it helped. Do check my calculations.
NISHTHA.
a = 27, d= -4, an = -65.
On reversing the order, AP becomes:
-65, -61,..............19,23,27
Here, a= -65, d= 4, an= 27.
Now,
a11= a + (11-1)d
a11 = -65 + 10* 4
= -65 + 40
= -25.
Therefore, the eleventh term from the last is -25.
Hope it helped. Do check my calculations.
NISHTHA.
Answered by
3
given that,
last term = l = -65
no. of terms = n= 11
common difference= d = 23-27 = -4
we know that,
nth term from the end = l - (n-1)d
= -65 - (11-1)(-4)
= -65 +40
= -25
HOPE IT HELPS.. FOR QUERIES COMMENT
last term = l = -65
no. of terms = n= 11
common difference= d = 23-27 = -4
we know that,
nth term from the end = l - (n-1)d
= -65 - (11-1)(-4)
= -65 +40
= -25
HOPE IT HELPS.. FOR QUERIES COMMENT
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