Question

Find the 11 th term from the last term of the ap, 10,7,4,....62.​

Answer 1

Answer:

The sequence given is 10, 7, 4, ....-62.

First we need to find out number of terms in this sequence.

'a' = 10, 'd' = -3, last term = -62

t

n

=a+(n−1)d

⟹−62=10+(n−1)(−3)

⟹−62=13−3n

⟹3n=75orn=25.

The number of terms in the sequence is 25.

The 11th term from the end is same as the 15th term from the first.

So, t

15

=10+(15−1)(−3)

⟹t

15

=10+(14)(−3)

⟹t

15

=−32

.

The 11th term from the end is -32.