Find the 11 th terms from the last term of Ap : 10, 7 , 4 .. - 62 and also find the sum of the given ap
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Hey buddy here is your answer !!
AP : 10 ,7 ,4,-62
Sn = n/2 { 2a + (n-1) d }
= -62 / 2 { 2 × 10 + ( -62 - 1 ) -3 }
= -31 { 20 + (-63 ) × -3 }
= - 31 × 20 + 189
= -31 × 209
Where is mistake i don't know plz tell me what is wrong !!
AP : 10 ,7 ,4,-62
Sn = n/2 { 2a + (n-1) d }
= -62 / 2 { 2 × 10 + ( -62 - 1 ) -3 }
= -31 { 20 + (-63 ) × -3 }
= - 31 × 20 + 189
= -31 × 209
Where is mistake i don't know plz tell me what is wrong !!
rakeshmohata:
here n is not - 62..
11th term = a +(11-1)d = 10 +(10)(-3)= - 20
hence 11th term is - 20
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hope this answer useful to you mate
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