find the 11th of an ap 2+√3,7+√3,12+√3
Answers
Answer :52+√3
Given 2+√3 , 7+√3 , 12+√3
The series is in a,a+d,a+2d....
By comparing th both equations,we get
a= 2+√3
a+d = 7+√3
=> 2+√3 + d = 7+√3
=> d = 5
We have 'a' as first term 'a+d' as second term and 'a+2d' as third term .
Therefore,
11 term of an ap will be as a+10d = 2+√3+10(5) = 52+√3.
Therefore,
11th term of the series 2+√3,7+√3,12+√3 is 52+√3.
Explaination:
•For an arithmetic progression the series will be as a,a+d,a+2d,a+3d...
•So,we have to compare the series with the given series 2+√3,7+√3,12+√3....
• We will get the values of a and d .
• We know that from the series a,a+d,a+2d...first term will be a and second term will be a+d ,third term will be a+2d.
• We have to find out the 11th term,so that 11th term will be as a+10d.
• By substituting the values of a and d in a+10d
• We get the answer as 52+√3.
Therefore,the 11th term of ap is 52+√3.
Answer:
11 term of an ap will be as a+10d = 2+√3+10(5) = 52+√3. Therefore, 11th term of the series 2+√3,7+√3,12+√3 is 52+√3.