Question

Find the 11th team of the AP - 6-9,-12-15
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Answer 1

Solution:

Given A.P :

-6,-9,-12,-15,...

first term (a) = -6

common difference (d) = a2-a1

= -9-(-6)

= -9+6

= -3

$\boxed {n^{th} term = a_{n} = a+(n-1)d}$

$a_{11}=a+10d$

= -6+10×(-3)

= -6-30

= -36

Therefore,

11th term in A.P = -36

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Answer 2

Answer:

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lwans

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