Question

find the 11th term from end of the AP 10,7,4,...-62​

Answer 1

➠ AnSwer :-

➙ given :-

• a = 10
• d = (7-10) = -3
• l = -62
• n = 11

➙ To find :-

• 11th term from the end of the given AP

➙ SoLution :-

11th term from the end. =

➝{l -(n-1) × d}

➝{-62-(11-1)×(-3)}

➝(-62 +30) = -32

Hence,the 11th term from the end of given AP is -32

Answer 2

Answer:

a11 = -20

Step-by-step explanation:

AP = a1 , a2 , a3 .....an

Common Difference (d) = a2 - a1

NOTE : IN AN AP the COMMON DIFFERENCE IS ALWAYS SAME.

Given AP = 10,7,4,...-62

Common Difference (d) = a2 - a1

Common Difference (d) = 7 - 10

Common Difference (d) = -3

an = a + (n - 1)d

Here,

a11 = a + (11 - 1)d

a11 = a + 10d

a11 = 10 + 10 X (-3)

a11 = 10 - 30

a11 = -20

Hope it helps you.

Thanks !