Question

Find the 11th term from the last term of AP =27,23,19,,,,69

Answer 1

a= 69 ,d=4,n=11 an= a+(n-1)d. an=69+10×4. an=69+40. an = 109 I hope it will help u pl pl pl mark me brainlist

Answer 2

Answer:

-25

Step-by-step explanation:

Given : 27 , 23 , 19 ,...., - 65

To Find: Find the 11th term from the last term

Solution:

27 , 23 , 19 ,...., - 65

First term = a = 27 ,

Common difference d = $a_2 - a_1$

d = 23 - 27 = - 4

Rewrite the A..P in the reverse,

- 65 , - 61 , - 57 , ... 19 , 23 , 27

So, now

First term = a = - 65

Common difference = $a_2 - a_1$

d = - 61 - ( - 65 )

d = -61 + 65

d = 4

Since we are given that we are supposed to find the 11th term

So, n =11

Formula of nth term = $a_n=a+(n-1)d$

a= -65

d= 4

n =11

Substitute the values

$a_{11}= -65+(11-1)4$

$a_{11}= -65+(10)4$

$a_{11}= -65+40$

$a_{11}= -25$

Hence the 11th term from the last in A.P. is -25