Question

find the 11th term from the last term of the AP 12, 8 ,4 ....- 84​

Answer 1

THE ANSWER IS

first term=a=12

t2=8

t3=4

d=t2-t1

=8-12

= -4

we know that,

TN= a+(n-1)d

t11= 12+(11-1)-4

=12+10(-4)

=12+(-40)

=12-40

=-28

Answer 2

The $11^{th}$ of AP is -28

Step-by-step explanation:

$\ Given \ series:\\\\12, 8, 4, ......-84\\\\\ Find:\\\\11^{th} term = ?\\\\\ Solution:\\\\a= 12\\\\d= 8-12 = -4\\\\n= 11 \\\\t_n =?\\\\\ formula:\\\\t_n =a+(n-1)d\\\\\rightarrow t_{11} = 12+(11-1)(-4)\\\\\rightarrow t_{11} = 12+(10)(-4)\\\\\rightarrow t_{11} = 12-40\\\\\rightarrow t_{11} = -28$

OR

$11^{th} term = a+ 10d \\\\a= 12 \ and \ \ d= -4\\\\\ put \ the \ value \ of \ a \ and \ b \ in \ above \ equation\\\\ 12+10(-4)\\\\12-40\\\\-28$

Learn more:

• Finding term in AP: https://brainly.in/question/8150427