Question

Find the 11th term from the last term of the ap 27 23 19 ..........-65

Answer 1

a = 27
d - 4
t11 = a + (n-1)d
= 27 + (11-1)(-4)
= 27 + 10 x - 4
= 27 - 40
= - 13

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Answer 2

Reverse the AP ,

The new AP = -65,-61........27

a=-65. , d=4. , a11 = a +(n-1)d

=-65+10×4

-65+40 = -25

Therefore a11th term from last = _25