Question

find the 11th term from the last term (towards the first term) of the AP : 10, 7, 4,..........-62.​

Answer 1

Step-by-step explanation:

For this let reverse the AP..

now first term = a = -62

common difference = d = 3

now 11th term from this side is...

A11 = a+10d = -62+10(3) =-62 + 30 = -32

hence 11th term from the last is -32

Answer 2

$\boxed{QUESTION:-}$

Find the 11th term from the last term (towards the first term) of the AP : 10, 7, 4,..........-62?

$\boxed{SOLUTION:-}$

a=10

d=-3[7-10 or a2-a1]

an=-62

=>an=a+(n-1)d

-62=10+(n-1)×-3

-62-10=(n-1)×-3

-72=(n-1)×-3

$\frac{\cancel{72}}{\cancel{-3}}$ =n-1

=>24=n-1

24+1=n

25 =n

So 25 terms are there in total!

now, finding 11th term from 25th Term↓

→11thTerm=(25thterm-10 terms)

=>15th Term

=>a15=10+(15-1)×-3

a15=10+(14×-3)

a15=10+-42

a15= -32

Means,The 11th Term from the Last term is -32

$\mathcal{BE \: BRAINLY}$