Find the 11th term from the last term (towards the first term) of the AP : 10, 7, 4, . . ., – 62.
Answers
Answer:
-32
Step-by-step explanation:
10, 7, 4, . . ., -62 are in A.P
a = 10
d = 7 - 10 #d = a2 - a1
d = -3
an = -62
a + (n-1)d = -62 #nth term of A.P
10 + (n-1) -3 = -62
10 - 3 n + 3 = -62
- 3 n = -75
n = 25
∴ 25th term of the given A.P is -62.
11th term from the last term = 25 - 10
= 15th term
∵ We need to find the 15th term of the given A.P
a15 = a + (15 - 1) d
= 10 + (14) -3
= 10 - 42
= -32
So, the 11th term from the last term = 15th term from the first = -32.
Answer:
-20
Step-by-step explanation:
a+(n-1)d is the formula for finding the nth term of A.P.
Given that a = 10(first term)
d = -3(difference between a consecutive term)
∴ 11th term = 10+(11-1)(-3)
=10+10(-3)
=10+(-30)
=10-30=-20
So, the 11th term = -20.