Find the 11th term from the last term (towards the first term) of the A.P: 10,7,4,........,-62.
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- The sequence given is 10, 7, 4, ....-62.
- First we need to find out number of terms in this sequence.
- 'a' = 10, 'd' = -3, last term = -62
- t
- n
- =a+(n−1)d
- ⟹−62=10+(n−1)(−3)
- ⟹−62=13−3n
- ⟹3n=75orn=25.
- The number of terms in the sequence is 25.
- The 11th term from the end is same as the 15th term from the first.
- So, t
- 15
- =10+(15−1)(−3)
- ⟹t
- 15
- =10+(14)(−3)
- ⟹t
- 15
- =−32
- .
- The 11th term from the end is -32
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