Question

Find the 11th term from the last term (towards the first term) of the AP = 10, 7 ,4.. - 62 .​

Answer 1

Answer:

use this formula a+(n_1),d so a is the first no10 n is 11 and d is 10 -7 which is 3

Answer 2

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Step-by-step explanation:

The sequence given is 10, 7, 4, ....-62.

First we need to find out number of terms in this sequence.

'a' = 10, 'd' = -3, last term = -62

tn =a+(n−1)d

⟹ −62=10+(n−1)(−3)

⟹ −62=13−3n

⟹ 3n=75orn=25.

The number of terms in the sequence is 25.

The 11th term from the end is same as the 15th term from the first.

So, t15 =10+(15−1)(−3)

⟹t15 =10+(14)(−3)

⟹t15 =−32

The 11th term from the end is -32.

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