Math, asked by Anonymous, 10 months ago

Find the 11th term of an AP -3, -\frac{1}{2}, 2....

Answers

Answered by mysticd
1

Answer:

 \red {11^{th} \:term} \green {= 22}

Step-by-step explanation:

 Given \:A.P : -3,\frac{-1}{2} ,2, \cdot\cdot\cdot

 First \:term (a) = -3

 common\: difference (d) = a_{3} - a_{2}\\= 2 - \frac{-1}{2} \\=2+\frac{1}{2}\\= \frac{ 4+1}{2} \\= \frac{5}{2}

 \boxed { \pink { n^{th}\:term (a_{n}) = a+(n-1)d}}

 11^{th} \:term(a_{11} ) = a + 10d \\= -3+10\times \frac{5}{2}\\= -3 + 25\\= 22

Therefore.,

 \red {11^{th} \:term} \green {= 22}

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Answered by priyagokul
0

Answer:

answer=22 hope it's help yiu

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