Question

Find the 11th term of AP : -5 , -5/2 , 0 , 5/2.......​

Answer 1

Answer:

a= -5 d= -5/2- (-5)

=-5/2+5

=-5+10/2

=5/2

T11 = a+(n-1)d

= -5+(11-1)5/2

=-5+10×5/2

=-5+50/2

=-5+25

=20

Answer 2

Answer:

a= -5

d= a2-a1

=-5/2+5

= -5+10/2

= 5/2

an= a+(n-1)d

a11=-5+(11-1)5/2

= -5+(10×5/2)

= -5+5×5

= -5+25

= 20

so 11th term of an AP is 20

Step-by-step explanation:

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