find the 11th term of from the last term of the AP10,7,4_ _ _ _ 62
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Answer:
a11=
Step-by-step explanation:
a=62
an=-10
d=-7-(-10) =-7+10=3 (from last, the first term in order becomes negative)
a11=a+10d
=62+10(3)
=62+30
=92
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